You should be able to see the rank of "last month" "last three month" "last year" and "oberall".
When you become inactive your overall rank will slowly decrease as skint said.
With this new kuskis could just check the "last month" because they would probably be very bad in "overall". Just an idea though.
I m not clear if i understood zebra right:
Yeah the time spent on a lev could be counted too but i'm afraid that the system goes too complicated that way.
Does that mean mila can get these times or were you talkin about assumed case that he can get the times
If he can, the system wouldn t be complicated at all - there would be only one more calulation to get in stats or nat (but you should be able to choose)
Then for mila's ranking algorithm i don t get why "e" is needed in this. Seems way to complicated imo.
Maybe i don t understand it right, so this is what i think it does:
In my example, when I m talin bout C(n)-D(n) or sach i m talkin bout the whole "(exp* xxx)" thing
A(n+1):
Lets say q is like 0,1, then exp(q*(B(n)-A(n)) would be between0,09999 and nearly 0 and when k is like 0,01 it s between 0,00099999 and nearly 0
So the same with C(n)-A(n) is a bit smaller and D(n)-A(n) even smaller.
A(n+1)=Old Rank * 1,0005 *1,0003 *1,0001 =Old Rank * 1,0009...
Sounds nice here.
B(n+1):
B(n)-A(n) as before --> like 1,0005
C(n)-B(n) could be the same as B(n)-A(n) but also greater or lesser
D(n)-B(n) is smaller than C(n)-B(n)
B(n+1) = (OLD Rank / 1,0005) * 1,0005 * 1,0003 = Old Rank * 1,0003
I Wasn t sure about the "()" but i think the way i put them in my example are quite logical
Sounds nice here too.
C(n+1):
C(n)-A(n) is like small
C(n)-B(n) is bigger than (C(n)-A(n)
D(n)-C(n) can be greater lesser or same as C(n)-B(n)
C(n+1) = Old rank / (1,0004 *1,0005) * 1,0005 = Old Rank /1,0004
okay
D(n+) Would then be something like Dn /XXX
So when i got this right, in general the upper part of the battle will slightly increase (or when u are very good but only become 10th out of 20 decrease) and all others will slightly decrease.
So when i got this right, this seems quite max system.