Oops, my mistake, edited last post now...
Right, Is
thiswhat you mean Jalli? (heh heh, I made that on paint)
Heres what I got so far...
If the sides of the square are 2, then the hypotenuse is Root8. With the radii of the circles added on, this makes the Diameter of S Root8 + 2.
Also, you take away two radii from root8 to get the diameter of T...Root8 - 2
So, the formula of the area of a circle is Pi.r^2, so you have to divide those diameters by two...but because root 8 isn't an integer its really hard...so thats where i gave up.
Anywhere near anything Jalli?